Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.3 - Properties of Logarithms - Exercise Set - Page 475: 20

Answer

$\frac{1}{7} \cdot \ln{x}$

Work Step by Step

RECALL: (1) $\sqrt[n]{x} = x^{\frac{1}{n}}$ (2) $\ln{(b^x)}=x$ (3) $\ln{(a^n)} = n \cdot \ln{a}$ Use rule (1) above to obtain $=\ln{(x^{\frac{1}{7}})}$ Use rule (3) above to obtain: $=\frac{1}{7} \cdot \ln{x}$
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