Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.3 - Properties of Logarithms - Exercise Set - Page 475: 67

Answer

$\ln\sqrt[3]{\dfrac{(x+5)^{2}}{x(x^{2}-4)}}$

Work Step by Step

$\displaystyle \frac{1}{3}[2\ln(x+5)-\ln x-\ln(x^{2}-4)]=$ ... move the 2 in the first term by applying the power rule $=\displaystyle \frac{1}{3}[\ln(x+5)^{2}-\ln x-\ln(x^{2}-4)]$ ... apply the quotient rule $=\displaystyle \frac{1}{3}[\ln\frac{(x+5)^{2}}{x}-\ln(x^{2}-4)]$ ... apply the quotient rule again $=\displaystyle \frac{1}{3}\cdot\ln[\frac{(x+5)^{2}}{x(x^{2}-4)}]$ ... move the $\displaystyle \frac{1}{3}$ by applying the power rule $=\displaystyle \ln[\frac{(x+5)^{2}}{x(x^{2}-4)}]^{1/3}$ ... write the rational exponent as a root (optional) $=\ln\sqrt[3]{\dfrac{(x+5)^{2}}{x(x^{2}-4)}}$
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