Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.3 - Properties of Logarithms - Exercise Set: 18

Answer

$-8 \cdot \log{M}$

Work Step by Step

RECALL: (1) $\log{\frac{M}{N}}=\log{M}-\log{N}$ (2) $\log{(b^x)}=x$ (3) $\log{(a^n)} = n \cdot \log{a}$ Use rule (3) above with $n=-8$ to obtain $=-8 \cdot \log{M}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.