Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Exercise Set: 9

Answer

$\approx 5.66$ units

Work Step by Step

Use the distance formula $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ to obtain: $d=\sqrt{(0-4)^2+(-3-1)^2} \\d=\sqrt{(-4)^2+(-4)^2} \\d=\sqrt{16+16} \\d=\sqrt{32} \\d \approx 5.66$
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