Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Exercise Set: 7

Answer

$\approx 5.39$ units

Work Step by Step

Use the distance formula $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ to obtain: $d=\sqrt{(-2-3)^2+(-6-(-4))^2} \\d=\sqrt{(-5)^2+(-6+4)^2} \\d=\sqrt{25+(-2)^2} \\d=\sqrt{25+4} \\d=\sqrt{29} \\d \approx 5.39$
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