Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Exercise Set - Page 280: 15

Answer

$d\approx 9.64$

Work Step by Step

RECALL: The distance between the points $(x_1, y_1)$ and $x_2, y_2)$ can be found using the distance formula: $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ Solve for the distance between the two points using the formula above to obtain: $d=\sqrt{[3\sqrt3-(-\sqrt{3})]^2+(\sqrt{5}-4\sqrt{5})^2} \\d=\sqrt{(3\sqrt3+\sqrt3)^2+(-3\sqrt5)^2} \\d=\sqrt{(4\sqrt3)^2+9(5)} \\d=\sqrt{16(3)+45} \\d=\sqrt{48+45} \\d=\sqrt{93} \\d\approx 9.64$
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