Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Exercise Set: 37

Answer

$(x+3)^2+(y+1)^2=3$

Work Step by Step

RECALL: The standard equation of a circle whose center is at $(h, k)$ and has a radius of $r$ units is: $(x-h)^2 + (y-k)^2 = r^2$ The given circle has its center at $(-3, -1)$ and a radius of $\sqrt3$ units. Thus, the standard form of the circle's equation is: $(x-(-3))^2+(y-(-1))^2=(\sqrt3)^2 \\(x+3)^2+(y+1)^2=3$
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