Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Exercise Set: 16

Answer

$d\approx 11.09$

Work Step by Step

RECALL: The distance between the points $(x_1, y_1)$ and $x_2, y_2)$ can be found using the distance formula: $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ Solve for the distance between the two points using the formula above to obtain: $d=\sqrt{[2\sqrt3-(-\sqrt{3})]^2+(\sqrt{6}-5\sqrt{6})^2} \\d=\sqrt{(2\sqrt3+\sqrt3)^2+(-4\sqrt6)^2} \\d=\sqrt{(3\sqrt3)^2+16(6)} \\d=\sqrt{9(3)+96} \\d=\sqrt{27+96} \\d=\sqrt{123} \\d\approx 11.09$
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