Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 1 - Section 1.9 - Distance and Midpoint Formulas; Circles - Exercise Set: 17

Answer

$d\approx 2.24$

Work Step by Step

RECALL: The distance between the points $(x_1, y_1)$ and $x_2, y_2)$ can be found using the distance formula: $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ Solve for the distance between the two points using the formula above to obtain: $d=\sqrt{(\frac{7}{3}-\frac{1}{3})^2+(\frac{1}{5}-\frac{6}{5})^2} \\d=\sqrt{(\frac{6}{3})^2+(-\frac{5}{5})^2} \\d=\sqrt{2^2+1^2} \\d=\sqrt{4+1} \\d=\sqrt{5} \\d\approx 2.24$
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