Thinking Mathematically (6th Edition)

Published by Pearson
ISBN 10: 0321867327
ISBN 13: 978-0-32186-732-2

Chapter 10 - Geometry - 10.2 Triangles - Exercise Set 10.2 - Page 629: 41

Answer

Total length of cable required is\[45\text{ yards}\].

Work Step by Step

The height of flagpole is 16 yards which are supported by 3 cables attached to the flagpole and is 4 yards just below the flagpole. Also, the cable attached to the ground is at a distance of 9 yards from the base of the flagpole. Let the height of flagpole till where the cable is attached be a and solve for the same using the equation as shown below. \[\begin{align} & a=\text{Height of flagpole}-\text{Distance between top of flagpole and cable point} \\ & a=16\text{ yards}-4\text{ yards} \\ & a=12\text{ yards} \end{align}\] Let b be the distance from the base of the flagpole to the point where the cable is attached to the ground and c be the length of 1 cable. Hence, \[a=12\]and\[b=9\]. Compute the value of \[c\]by using Pythagorean Theorem and By using formula \[\begin{align} & {{c}^{2}}={{a}^{2}}+{{b}^{2}} \\ & {{c}^{2}}={{12}^{2}}+{{9}^{2}} \end{align}\] Now if\[{{12}^{2}}=12.12=144\], \[{{9}^{2}}=9.9=81\]then solve for c using the equation as shown below. \[\begin{align} & {{c}^{2}}=144+81 \\ & {{c}^{2}}=225 \\ & c=\sqrt{225} \\ & c=15 \\ \end{align}\] Therefore, the length of 1 cable is 15 yards. Compute the length 3 cables as follows: \[\begin{align} & \text{Length of }3\text{ cables}=3\times \text{Length of }1\text{ cable} \\ & =3\times 15 \\ & =45\text{ yards} \end{align}\] Hence, the total length of cable required is\[45\text{ yards}\].
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