Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 13 - Vector Functions - 13.1 Exercises - Page 870: 25

Answer

Graph IV

Work Step by Step

Because $\sin^{2}A+\cos^{2}A=1$, the x and y coordinates satisfy $x^{2}+y^{2}=1$ So, as z changes, this circle translates into a cylinder propagating around the z-axis. The curve will lie on this cylinder. Two graphs offer upright cylinders with circular coils, IV and VI. When t=0, the point on the graph is (1,0,1) When t=$\pi/4,$ a full circle was made by the x and y coordinates, while z fell to slightly more than 0.5 (this is the difference between cylinders IV and VI). Thus, the answer is Graph IV.
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