Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 13 - Vector Functions - 13.1 Exercises - Page 870: 14

Answer

See image

Work Step by Step

Parametric equations: $\left\{\begin{array}{l} x=\cos t\\ y=-\cos t\\ z=\sin t \end{array}\right.$ Because $\sin^{2}A+\cos^{2}A=1$, all the points lie in the plane $y=-x$, and $x^{2}+z^{2}=1,$ so this is a circle in that plane.
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