Multivariable Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 0-53849-787-4
ISBN 13: 978-0-53849-787-9

Chapter 13 - Vector Functions - 13.1 Exercises - Page 870: 21

Answer

Graph II.

Work Step by Step

Because $\sin^{2}A+\cos^{2}A=1$, the x and z coordinates satisfy $x^{2}+z^{2}=t^{2}$ and the points on the curve satisfy $x^{2}+z^{2}=y^{2}$ so the curve will spiral into ever increasing circles as y increases. (this describes a spiral along a circular cone opening along the y-axis). The additional condition, $t\geq 0$ means that the propagation takes place only along the positive y axis. This is graph II.
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