## Calculus: Early Transcendentals 8th Edition

$-5x^{\frac{7}{5}}+40x^{\frac{1}{5}} +C$
Start with the function $\int (-7x^{2/5} + 8x^{-4/5})dx$. Use the power rule for antiderivatives to integrate each term: $-\frac{7x^{7/5}}{\frac{7}{5}}+\frac{8x^{1/5}}{\frac{1}{5}}+C$ Simplify the fractions to arrive at answer: $-5x^{\frac{7}{5}}+40x^{\frac{1}{5}} +C$