Answer
$5x^{\frac{7}{5}}+40x^{\frac{1}{5}} +C$
Work Step by Step
Start with the function $\int (7x^{2/5} + 8x^{-4/5})dx$.
Use the power rule for antiderivatives to integrate each term:
$\frac{7x^{7/5}}{\frac{7}{5}}+\frac{8x^{1/5}}{\frac{1}{5}}+C$
Simplify the fractions to arrive at answer:
$5x^{\frac{7}{5}}+40x^{\frac{1}{5}} +C$
