Answer
$F(x)=x-2\cos x+6\sqrt{x}+C$
Work Step by Step
From the Table of Antiderivatives,
$f(x)=1\displaystyle \cdot x^{0}\quad \Rightarrow\quad F(x)=1\cdot\frac{x^{1}}{1}+C=x+C$
$f(x)=2\sin x\quad \Rightarrow\quad F(x)=-2\cos x+C$
$f(x)=3\displaystyle \cdot x^{-1/2}\quad \Rightarrow\quad F(x)=3\cdot\frac{x^{1/2}}{1/2}+C=6\sqrt{x}+C$
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$F(x)=x-2\cos x+6\sqrt{x}+C$
