Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 4 - Section 4.9 - Antiderivatives - 4.9 Exercises: 4

Answer

$x^{6} - \frac{8x^{5}}{5}-3x^{3} + C$

Work Step by Step

$\int(6x^{5}-8x^{4}-9x^{2})dx$ Use power rule for antiderivatives (antiderivative of $x^{n}$ is $\frac{x^{n+1}}{n+1}$) on each of the three terms: $\frac{6}{6}x^{6} - \frac{8x^{5}}{5}-\frac{9}{3}x^{3} + C$ Simplify: $x^{6} - \frac{8x^{5}}{5}-3x^{3} + C$
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