Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 4 - Section 4.9 - Antiderivatives - 4.9 Exercises - Page 355: 19

Answer

$F(x)=\displaystyle \frac{2^{x}}{\ln 2}+4\cosh x+C$

Work Step by Step

From the Table of Antiderivatives, $f(x)=b^{x}\displaystyle \quad \Rightarrow\quad F(x)=\frac{b^{x}}{\ln b}+C$ $f(x)=\sinh x\quad \Rightarrow\quad F(x)=\cosh x+C$ --- $f(x)=2^{x}+4\sin h$ $F(x)=\displaystyle \frac{2^{x}}{\ln 2}+4\cosh x+C$
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