Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 4 - Section 4.9 - Antiderivatives - 4.9 Exercises: 9

Answer

$x\sqrt 2+C$

Work Step by Step

$\int\sqrt 2 dx$ When taking the antiderivative of a constant, we use the power rule to find that the constant simply is multiplied by $x$. With a constant of$ \sqrt 2$, the antiderivative is thus $x\sqrt 2+C$.
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