Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 4 - Section 4.9 - Antiderivatives - 4.9 Exercises: 14

Answer

$F(t)=3t-\ln|t|-\frac{6}{t}+C$, $t\ne 0$

Work Step by Step

$f(t)=\frac{3t^{4}-t^{3}+6t^{2}}{t^{4}}$ Dividing out, we get: $f(t)=3-\frac{1}{t}+\frac{6}{t^{2}}$ These follow basic antiderivative rules. $F(t)=3t-\ln|t|-\frac{6}{t}+C$, $t\ne 0$
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