## Calculus: Early Transcendentals (2nd Edition)

a) $(f\circ g)(2)=4$ b) $g(f(2))=1$ c) $f(g(4))=3$ d) $g(f(5))=3$ e) $f(f(8))=8$ f) $g(f(g(5)))=1$
a) $(f\circ g)(2)=f(g(2))=f(2)=4$ b) $g(f(2))=g(4)=1$ c) $f(g(4))=f(1)=3$ d) $g(f(5))=g(6)=3$ e) $f(f(8))=f(8)=8$ f) $g(f(g(5)))=g(f(2))=g(4)=1$