Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 1 - Functions - 1.1 Review of Functions - 1.1 Exercises: 29

Answer

$1/(y^3-3)$

Work Step by Step

We know that $F(x)=1/(x-3)$ and $g(x)=x^3$, so: $F(g(y))=F(y^3)=1/(y^3-3)$
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