Answer
$\frac{x-3}{10-3x}$
Work Step by Step
We know that $F(x)=1/(x-3)$, so:
$F(F(x))=\frac{1}{\frac{1}{x-3}-3}=\frac{1}{\frac{1}{x-3}-\frac{3(x-3)}{(x-3)}}=\frac{1}{\frac{1-3x+9}{x-3}}=\frac{1}{\frac{10-3x}{x-3}}=\frac{x-3}{10-3x}$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 1 - Functions - 1.1 Review of Functions - 1.1 Exercises - Page 10: 33
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