Answer
$1/(x^2-7)^3$
Work Step by Step
We know that $g(x)=x^3$ and $F(x)=1/(x-3)$ and $f(x)=x^2-4$, so:
$g(F(f(x))=g(F(x^2-4))=g(1/(x^2-4-3))=g(1/(x^2-7))=1/(x^2-7)^3$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 1 - Functions - 1.1 Review of Functions - 1.1 Exercises - Page 10: 34
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