Answer
$f(x) =x^2 $
Work Step by Step
$(f ∘ g)(x) = x^4+6x^2+20=(x^2+3)^2$
$g(x)=x^2+3$
$(f ∘ g)(x) = f(g(x)) = f(x^2+3) =(x^2+3)^2$
Therefore lets choose $f(x) =x^2 $
$(f ∘ g)(x) = f(g(x)) =(g(x))^2=(x^2+3)^2$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 1 - Functions - 1.1 Review of Functions - 1.1 Exercises - Page 10: 51
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