Answer
$4+h$
Work Step by Step
We know that $f(x)=x^2−4$, so:
$\frac{f(2+h)-f(2)}{h}=\frac{[(2+h)^2-4]-[2^2-4]}{h}=\frac{4+4h+h^2-4-0}{h}=4+h$
Calculus: Early Transcendentals (2nd Edition)
by Briggs, Bill L.; Cochran, Lyle; Gillett, Bernard
Published by
Pearson
ISBN 10:
0321947347
ISBN 13:
978-0-32194-734-5
Chapter 1 - Functions - 1.1 Review of Functions - 1.1 Exercises - Page 10: 32
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