## Calculus 8th Edition

$\int\frac{log_{10}x}{x}dx=\frac{x^{2}}{2ln10}$
Evaluate the integral $\int\frac{log_{10}x}{x}dx$ Apply Logarithmic base formula. $\int\frac{log_{10}x}{x}dx=\int\frac{lnx}{x(ln10)}$ Hence, $\int\frac{log_{10}x}{x}dx=\frac{x^{2}}{2ln10}$