Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.4* General Logarithmic and Exponential Functions - 6.4* Exercise: 45

Answer

$\int_0^42^{s}ds=\frac{15}{ln2}$

Work Step by Step

Evaluate the integral $\int_0^42^{s}ds$. $\int_0^42^{s}ds=|\frac{2^{s}}{ln2}|_0^4$ $=\frac{2^{4}-2^{0}}{ln2}$ $=\frac{16-1}{ln2}$ Hence, $\int_0^42^{s}ds=\frac{15}{ln2}$
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