Answer
$\frac{6}{u}(ln10)(10^{lnu})(1+10^{lnu})^{5}$
Work Step by Step
$\frac{d}{du}G(u)=\frac{d}{dx}(1+10^{lnu})^{6}$
$=6(1+10^{lnu})^{5}(10^{lnu})ln10\frac{d}{dx}lnu$
Hence, $G'(u)=\frac{6}{u}(ln10)(10^{lnu})(1+10^{lnu})^{5}$
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