Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.4* General Logarithmic and Exponential Functions - 6.4* Exercise: 29

Answer

$2vsec^{2}(4^{v^{2}}) 4^{v^{2}}ln4$

Work Step by Step

Let $L'(v)$ be the derivative of the function $tan(4^{v^{2}})$. $L'(v)=\frac{d}{dv}tan(4^{v^{2}})$ $=sec^{2}4^{v^{2}}\frac{d}{dv}(4^{v^{2}})$ $=sec^{2}4^{v^{2}} 4^{v^{2}}ln4\frac{d}{dv}{(v^{2}})$ $=2vsec^{2}(4^{v^{2}}) 4^{v^{2}}ln4$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.