Answer
$\frac{3^{sin\theta}}{ln3}+C$
Work Step by Step
Evaluate the integral $\int 3^{sin \theta} cos\theta d\theta$
Consider ${sin \theta}=x$
$cos\theta d \theta=dx$
$\int 3^{sin \theta} cos\theta d\theta=\int3^{x}dx$
This implies
$\int 3^{sin \theta} cos\theta d\theta= \frac{3^{sin\theta}}{ln3}+C$
