Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 522: 67

Answer

$\dfrac{1}{y^{\frac{1}{6}}}$

Work Step by Step

Use the rule $(a^m)^n= a^{mn}$ to obtain: $=y^{-\frac{2}{3} \cdot \frac{1}{4}} \\=y^{-\frac{2(1)}{3(4)}} \\=y^{-\frac{2}{12}} \\=y^{-\frac{1}{6}}$ Use the rule $a^{-m} = \dfrac{1}{a^m}$ to obtain: $=\dfrac{1}{y^{\frac{1}{6}}}$
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