Answer
$x^{9}y^{15}$
Work Step by Step
Simplify. $(\sqrt [4]{{x^3y^5}})^{12}$
Since, $\sqrt[n] {p^m}=p^{\frac{m}{n}}$
Thus,
$(\sqrt [4]{{x^3y^5}})^{12}=(x^3y^5)^{\frac{12}{4}}=(x^3y^5)^{3}$
or, $=(x^3)^{3}(y^5)^3$
or, $=x^{9}y^{15}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 522: 109
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