Answer
$\dfrac{2x^3}{y}$
Work Step by Step
Simplify. $(8x^{-6}y^3)^{1/3}(x^{5/6}y^{-1/3})^6$
or, $=(2^3)^{1/3}(x^{-6})^{1/3}(y^3)^{1/3}(x^{5/6})^6(y^{-1/3})^6$
or,$=2(x^{-2})(y)(x^{5})(y^{-2})$
or, $=2x^{-2+5}y^{1+(-2)}$
or, $=2x^3y^{-1}$
or, $=\dfrac{2x^3}{y}$
