Answer
$\frac{7x}{z^{\frac{1}{4}}}$
Work Step by Step
$z^{-\frac{1}{4}}$ is a non-zero real number thus $z^{-\frac{1}{4}}=\frac{1}{z^{\frac{1}{4}}}$
Thus $7xz^{-\frac{1}{4}}=\frac{7x}{z^{\frac{1}{4}}}$
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