Answer
$4$
Work Step by Step
RECALL:
(i) $\dfrac{a^m}{a^n} = a^{m-n}$
(ii) $a^{\frac{m}{n}}=\sqrt[n]{a^m}$
Use the rules above to obtain:
$=16^{\frac{3}{4} - \frac{1}{4}}
\\=16^{\frac{2}{4}}
\\=16^{\frac{1}{2}}
\\=\sqrt{16}
\\=4$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 522: 57
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