Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 522: 111

Answer

$\sqrt [4] {a^3b^3 }$.

Work Step by Step

The given expression is $\frac{\sqrt[4] {a^5b^5}}{\sqrt {ab}}$ Use $\sqrt[n] x =x^{\frac{1}{n}}$. $=\frac {\left ( a^5b^5 \right )^{\frac{1}{4}} }{\left ( ab \right )^{\frac{1}{2}}}$ Use $\frac{1}{x^{n}}=x^{-n}$. $=\left ( a^5b^5 \right )^{\frac{1}{4}} \cdot \left ( ab \right )^{-\frac{1}{2}}$ Use $(ab)^m=a^mb^m$. $=a^{\frac{5}{4}}b^{\frac{5}{4}} \cdot a^{-\frac{1}{2}}b^{-\frac{1}{2}}$ Use $a^m\cdot a^n=a^{m+n}$. $=a^{\frac{5}{4}-\frac{1}{2}}b^{\frac{5}{4}-\frac{1}{2}} $ $=a^{\frac{5-2}{4}}b^{\frac{5-2}{4}} $ $=a^{\frac{3}{4}}b^{\frac{3}{4}} $ Use $a^mb^m=(ab)^m$. $=\left ( a^3b^3 \right )^{\frac{1}{4}}$ Use $x^{\frac{1}{n}}=\sqrt[n] x $. $=\sqrt [4] {a^3b^3 }$.
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