Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Test - Page 599: 29

Answer

$230$ more, 6.5%

Work Step by Step

3000 to invest for 10 years 6.5% compounded semiannually $P=3000$ $n=2$ $t=10$ $r=.065$ $A=P*(1+(r/n))^{n*t}$ $A=3000*(1+(.065/2))^{2*10}$ $A=3000*(1.0325^{20})$ $A=3000*1.895838$ $A=5687.51$ 6% compounded monthly $P=3000$ $n=12$ $t=10$ $r=.06$ $A=P*(1+(r/n))^{n*t}$ $A=3000*(1+(.06/12))^{12*10}$ $A=3000*(1.005^{120})$ $A=3000*1.819396$ $A=5458.19$ $5687.51-5458.19=229.32$
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