Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Test - Page 599: 17

Answer

$x=-1$

Work Step by Step

Expressing both sides of the equation in the same base to equate the exponents, then, \begin{array}{l} 8^{x-1}=\dfrac{1}{64} \\\\ 8^{x-1}=\dfrac{1}{8^2} \\\\ 8^{x-1}=8^{-2} \\\\ x-1=-2 \\\\ x=-1 .\end{array}
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