Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Test - Page 599: 20

Answer

$x=\dfrac{1}{2}$

Work Step by Step

Using properties of logarithms, then, \begin{array}{l} \ln \sqrt{e}=x \\\\ \ln e^{\frac{1}{2}}=x \\\\ \dfrac{1}{2}\ln e=x \\\\ \dfrac{1}{2}(1)=x \\\\ x=\dfrac{1}{2} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.