Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Test - Page 599: 15

Answer

$-1.53$

Work Step by Step

Using the properties of logarithms and the given values of logarithmic expressions, then, \begin{array}{l} \log_b \dfrac{3}{25} \\\\= \log_b 3-\log_b 25 \\\\= \log_b 3-\log_b 5^2 \\\\= \log_b 3-2\log_b 5 \\\\= 0.79-2(1.16) \\\\= -1.53 .\end{array}
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