Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Test - Page 599: 19

Answer

$x=\dfrac{1}{9}$

Work Step by Step

Since $\log_b x=y$ implies $b^y=x$, then, \begin{array}{l} \log_3 x=-2 \\\\ x=3^{-2} \\\\ x=\dfrac{1}{3^{2}} \\\\ x=\dfrac{1}{9} .\end{array}
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