Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Test - Page 599: 12

Answer

$=\log_3 24$

Work Step by Step

Using properties of logarithms, then, \begin{array}{l} \log_3 6+\log_3 4\\\\ =\log_3 (6\cdot4)\\\\ =\log_3 24 .\end{array}
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