Answer
$x=\frac{e^{2}-1}{3}$
Work Step by Step
We are given the equation $\ln(3x+1)=2$. To solve for x, remember that the base of a natural logarithm is understood to be $e$.
Therefore, $\ln(3x+1)=log_{e}(3x+1)=2$.
If $b\gt0$ and $b\ne1$, then $y=log_{b}x$ means $x=b^{y}$ for every $x\gt0$ and every real number $y$.
Therefore, $3x+1=e^{2}$.
Subtract 1 from both sides.
$3x=e^{2}-1$
Divide both sides by 3.
$x=\frac{e^{2}-1}{3}$