Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review - Page 597: 49

Answer

$(\frac{1}{2})^{-4}=16$

Work Step by Step

If $b\gt0$ and $b\ne1$, then $y=log_{b}x$ means $x=b^{y}$ for every $x\gt0$ and every real number $y$. Therefore, $log_{\frac{1}{2}}16=-4$ means $(\frac{1}{2})^{-4}=16$.
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