## Intermediate Algebra (6th Edition)

To approximate $log_{3}4$, we can use the change of base formula, which can be written as $log_{b}a=\frac{log_{c}a}{log_{c}b}$ (where a, b, and c are positive real numbers and neither b nor c is equal to 1). In this case, we will write $log_{3}4$ in base 10, which is in the form of the common logarithm. Therefore, $log_{3}4=\frac{log_{10}4}{log_{10}3}=\frac{.6021}{.4771}=1.2619$