Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review: 93

Answer

.2920

Work Step by Step

To approximate $log_{5}1.6$, we can use the change of base formula, which can be written as $log_{b}a=\frac{log_{c}a}{log_{c}b}$ (where a, b, and c are positive real numbers and neither b nor c is equal to 1). In this case, we will write $log_{5}1.6$ in base 10, which is in the form of the common logarithm. Therefore, $log_{5}1.6=\frac{log_{10}1.6}{log_{10}5}=\frac{.2041}{.6990}=.2920$
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