Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review: 97

Answer

$x=\frac{log(7)}{2log(3)}\approx.8856$

Work Step by Step

According to the logarithm property of equality $log_{b}a=log_{b}c$ is equivalent to $a=c$ (where a, b, and c are real numbers such that $log_{b}a$ and $log_{b}c$ are real numbers and $b\ne1$). We can use this property to solve for x. $3^{2x}=7$ Take the common logarithm of both sides (which has base 10). $log(3^{2x})=log(7)$ Use the power property of logarithms. $2x log(3)=log(7)$ Divide both sides by $2log(3)$. $x=\frac{log(7)}{2log(3)}\approx.8856$
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