Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review - Page 597: 64

Answer

Please see the graph.

Work Step by Step

The green line is the function $y=(1/2)^x$. The purple line is $y=log_{1/2} x$. $y=(1/2)^x$ $x=0$ $y=(1/2)^x$ $y=(1/2)^0$ $y=1$ $x=1$ $y=(1/2)^x$ $y=(1/2)^1$ $y=1/2$ $x=2$ $y=(1/2)^x$ $y=(1/2)^2$ $y=1/4$ $(0,1)$, $(1,1/2)$, and $(2,1/4)$ are on the curve of the function $y=(1/2)^x$. $y=log_{1/2} x$ $x=1$ $y=log_{1/2} x$ $y=log_{1/2} 1$ $(1/2)^y=1$ $(1/2)^0=1$ $y=0$ $x=.5$ $y=log_{1/2} x$ $y=log_{1/2} (1/2)$ $(1/2)^y=(1/2)$ $.5^1=.5$ $y=1$ $x=.25$ $y=log_{1/2} x$ $y=log_{1/2} (1/4)$ $(1/2)^y=(1/4)$ $(1/2)^2=(1/4)$ $y=2$ $(1,0)$, $(1/2,1)$, and $(1/4,2)$ are on the curve of the function $y=log_{1/2} x$.
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