Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review - Page 600: 8b

Answer

$-\dfrac{8}{27}$

Work Step by Step

Using the properties of exponents, then, \begin{array}{l} \left( -\dfrac{2}{3} \right)^3 \\\\ \left( \dfrac{-2}{3} \right)^3 \\\\ \dfrac{(-2)^3}{(3)^3} \\\\ \dfrac{-8}{27} \\\\ -\dfrac{8}{27} .\end{array}
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