Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review - Page 600: 8e

Answer

$a^4*c^8/b^6$

Work Step by Step

$(a^{-2}*b^3*c^{-4})^{-2}$ $(b^3/a^2c^4)^{-2}$ $1/(b^3/a^2c^4)^2)$ $1/(b^6/a^4c^8)$ $(a^4c^8)*1/(a^4c^8)*(b^6/a^4c^8)$ $a^4*c^8/b^6$
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